Question

i dont solve it properly​

Answer 1

Answer:

$\frac{dx( \cot) } {dx} = {cosec}^{2}x$

The derivative of cot x with respect to x is -1 times the square of csc x. i.e., d/dx(cot x) = -csc2x. It can also be written as (cot x)' = -csc2x.

Answer 2

$\begin{gathered}\\ \tt{:}\dashrightarrow \frac{d}{dx}(cot\:x)\end{gathered}$

Use $\frac{d}{dx} ( \cot(x) ) = - \csc(x) ^{2}$ to solve derivative

$\begin{gathered}\\ \tt{:}\dashrightarrow -csc(x)^{2}\end{gathered}$