I f n (A):=5 & n(3) = 7 then the number of relations
from A to B is
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Answer:
According to the Formula,
2^n(A)×n(B)
Given,
n(A)=5 ; n(B)=7
By applying in the formula,
2^5×7
2^35
34359738368.
So,the relation from A to B is 34359738368
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