I find perimeter of a square if its diagonal is 10√2 cm
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Answer:
Solution :
Let the side of the square = a
Diagonal ( d ) = 10√2
=> √2 a = 10√2
=> a = 10√2/√2
a = 10 cm ---( 1 )
Perimeter = 4a
P = 4 × 10
P = 40 cm
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