(i) Find simple interest paid on ₹ 6000 at 5% p.a. for 4 years? (ii) In what time ₹ 300 will yield ₹ 60 interest at 5% p.a. (iii) Find the rate per cent p.a. if ₹ 350 yields ₹ 105 interest in 6 years?
aman7863:
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Solutions :-
(i) Given :
Principle = p = ₹ 6000
Rate = r = 5% p.a
Time = t = 4 years
Simple Interest = S.I = ?
S.I = (p × r × t)/100
= (6000 × 5 × 4)/100
= Rs 1200
Amount (A) = S.I + p
= ₹ (1200 + 6000) = ₹ 7200
Hence,
Simple Interest = ₹ 1200
Amount = ₹ 7200
_______________________
(ii) Given :
Principle = p = ₹ 300
Simple Interest = S.I = ₹ 60
Rate = r = 5% p.a
Time = t = ?
t = (S.I × 100)/(p × r)
= (60 × 100)/(300 × 5)
= 6000/1500
= 4
Hence,
Time = 4 years
_______________________
(iii) Given :
Principle = p = ₹ 350
Simple Interest = S.I = ₹ 105
Time = t = 6 years
Rate = r = ?
r = (S.I × 100)/(p × t)
= (105 × 100)/(350 × 6)
= 10500/2100
= 5
Hence,
Rate = 5 % p.a
_______________________
(i) Given :
Principle = p = ₹ 6000
Rate = r = 5% p.a
Time = t = 4 years
Simple Interest = S.I = ?
S.I = (p × r × t)/100
= (6000 × 5 × 4)/100
= Rs 1200
Amount (A) = S.I + p
= ₹ (1200 + 6000) = ₹ 7200
Hence,
Simple Interest = ₹ 1200
Amount = ₹ 7200
_______________________
(ii) Given :
Principle = p = ₹ 300
Simple Interest = S.I = ₹ 60
Rate = r = 5% p.a
Time = t = ?
t = (S.I × 100)/(p × r)
= (60 × 100)/(300 × 5)
= 6000/1500
= 4
Hence,
Time = 4 years
_______________________
(iii) Given :
Principle = p = ₹ 350
Simple Interest = S.I = ₹ 105
Time = t = 6 years
Rate = r = ?
r = (S.I × 100)/(p × t)
= (105 × 100)/(350 × 6)
= 10500/2100
= 5
Hence,
Rate = 5 % p.a
_______________________
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