Math, asked by vaishnavi2417, 1 year ago

(i) Find simple interest paid on ₹ 6000 at 5% p.a. for 4 years? (ii) In what time ₹ 300 will yield ₹ 60 interest at 5% p.a. (iii) Find the rate per cent p.a. if ₹ 350 yields ₹ 105 interest in 6 years?


aman7863: Hlo vaishnavi

Answers

Answered by Anonymous
118
Solutions :-


(i) Given :
Principle = p = ₹ 6000
Rate = r = 5% p.a
Time = t = 4 years
Simple Interest = S.I = ?

S.I = (p × r × t)/100
= (6000 × 5 × 4)/100
= Rs 1200

Amount (A) = S.I + p
= ₹ (1200 + 6000) = ₹ 7200

Hence,
Simple Interest = ₹ 1200
Amount = ₹ 7200


_______________________

(ii) Given :
Principle = p = ₹ 300
Simple Interest = S.I = ₹ 60
Rate = r = 5% p.a
Time = t = ?

t = (S.I × 100)/(p × r)
= (60 × 100)/(300 × 5)
= 6000/1500
= 4

Hence,
Time = 4 years


_______________________

(iii) Given :
Principle = p = ₹ 350
Simple Interest = S.I = ₹ 105
Time = t = 6 years
Rate = r = ?

r = (S.I × 100)/(p × t)
= (105 × 100)/(350 × 6)
= 10500/2100
= 5

Hence,
Rate = 5 % p.a
_______________________

piyushravat57: what
Anonymous: thanks bhai :)
Anonymous: ✨✨You rocked it ✌✌✌
Anonymous: thank you :)
deep9775: hool
deep9775: hi
LovelyBarshu: ROCKED THE ANSWER BHAI ✨
Anonymous: thanks :)
Answered by Anonymous
33
hey mate
refer to attachment
Attachments:

nighat54: nice
Similar questions