Question

(I) find the number which when increased by 30 percent becomes 39.
(II) Find the number which when decreased by 8 percent becomes 506.​

Answer 1

Answer:

(I) $30$

Step-by-step explanation:

If you dont know that number, you can think of it as a variable

(I)

let that number is $x$

increased by $30\%$, so

$x(1 + 30/100)=39$

by solving this equation, gives us

$x = 30$

(II)

let that number is $x$

decreased by $8\%$, so

$x(1 - 8/100) = 506$

then, you can use its as your exercise

Answer 2

Answer:

(I) 100% of the original number= (39×100)/130=30.

(II) 550

Step-by-step explanation:

(I) The original number+30% of the original number= 39

130% of the original number=39

100% of the original number=(39×100)/130=30.

OR

Let it be X

X+30% of X=39

X+0.3X= 39

1.3X = 39

X = 39/1.3= 30.

So the number is 30.

(II) Let number be X

Decrease=8% of X

8x/100=2×/25

according to the statement

x-2x/25=506

25x-2/25=506

23/25x=506

X=506×25/23=12650/23

=550

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