Question

I find the tenth term of Sequence √2,√8,√18​

Answer 1

Question:-

• Find the tenth term of the AP.

Solution:-

Given series,

$\sf \sqrt{2} = 1\sqrt{2}$

$\sf \sqrt{8} = 2 \sqrt{2}$

$\sf \sqrt{18} = \sf3 \sqrt{2}$

So,

$\sf a = \sqrt{2}$

$\sf d = \sqrt{2}$

Therefore,

$\sf T_{10} = a + (10 - 1)d$

$\sf = \sqrt{2} + 9 \sqrt{2}$

$\sf = 10 \sqrt{2}$

Therefore, the tenth term is $\sf 10\sqrt{2}$

Answer 2

Answer:

hey watch the above pic for ur answer

hope it helps .