Question

I find the value of a from the following
Sec A= cosec (A-20°)
tan3 A=sin 45°cos 45°+sin 30°

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Answer 1

Answer:

R.H.S

sin45°⋅cos45° +sin30= 1/root2.1/root 2 + 1/2

=1/2+1/2

=2/2

=1

Now,

L.H.S

tan3x=1

But tan45° =1

∴tan3x=tan45

⇒3x=45

⇒x= 45/3 = 15

∴x=15.