Question

I For what value of k, the roots of the equation x2 + 4x + k = 0 are real ?​

Answer 1

Answer:

value of k =4

Step-by-step explanation:

b^2=4ac

4^2= 4x1xk

16=4k

k=4

Answer 2

Answer:

by using discriminant formula

B^2 -4ac=0

or B^2-4ac=any value bigger than zero

then value will be real

Now, 4×4-4(1)(k)

=16-4k=0

16=4k

k=4

4 is the answer