i have a doubt bin half angle formula....how it was derived...I am queries in this formula base question
Answers
Answer:
okh let me tell you
Step-by-step explanation:
Half angle formulas can be derived from the double angle formulas, particularly, the cosine of double angle. For easy reference, the cosines of double angle are listed below:
cos 2θ = 1 - 2sin2 θ → Equation (1)
cos 2θ = 2cos2 θ - 1 → Equation (2)
Note that the equations above are identities, meaning, the equations are true for any value of the variable θ. The key on the derivation is to substitute θ with ½ θ.
For Equations (1) and (2), let θ = ½ θ
From Equation (1)
cos2(12θ)=1−2sin212θcos2(12θ)=1−2sin212θ
cosθ=1−2sin212θcosθ=1−2sin212θ
2sin212θ=1−cosθ2sin212θ=1−cosθ
sin12θ=1−cosθ2−−−−−−−−√sin12θ=1−cosθ2
From Equation (2)
cos2(12θ)=2cos212θ−1cos2(12θ)=2cos212θ−1
cosθ=2cos212θ−1cosθ=2cos212θ−1
2cos212θ=1+cosθ2cos212θ=1+cosθ
cos12θ=1+cosθ2−−−−−−−−√cos12θ=1+cosθ2
tan12θ=sin12θ
hope this will help you
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