Physics, asked by subhranshupattanayak, 6 months ago

I have a doubt can anyone solve this​

Attachments:

Answers

Answered by kingofdarkness865
1

Answer:

5 watt

Explanation:

work done = F . S

= (5i + 4j). ( 3i + 4k) = 5 * 3 + 4 * 0 + 0 * 4 = 15 joule

power = work done/time taken

= 15/3 joule per second = 5 watt

Answered by LoverLoser
8

\boxed{\bf{ \red{\bigstar Question \longrightarrow }}}

A force F= (5i +4j)N displaces a body through S= (3i + 4k)m in 3 sec. Find the power.

\boxed{\bf{ \blue{\bigstar Find \longrightarrow }}}

  • Power ??

\boxed{\bf{ \orange{\bigstar Given \longrightarrow }}}

  • \sf{Force [F]= (5 \hat i + 4 \hat j ) N }

\sf{distance[S] = 3 \hat i + 2 \hat k }

\boxed{\bf{ \green{\bigstar formulas \ used \longrightarrow }}}

  • \sf{ P= \dfrac{W}{t} }
  • \sf{W= F.S}

where,

P= Power,

W= Work done,

t= Time,

F= Force,

S= Distance.

\boxed{\bf{ \purple{\bigstar SoLution \longrightarrow }}}

firstly we will find the W {work done]

\sf{W= F.S}

put value in the formula we get,

\sf{W= (5\hat i + 4\hat j + 0 \hat k) + (3\hat i+0\hat j+4\hat k)}

\sf{W= ( 5 \times 3) + (4\times 0) + (0 \times 4 )}

W= 15J

now we will find the value of power,

\sf{ P= \dfrac{W}{t} }

put value of w and t in the formula we get,

\sf{ P = \dfrac{ 15}{3} = 5 }

\boxed{\sf{ P = 5 watt }}

\bf{\underline{\pink{\bigstar \therefore Power \ is \ 5 watt. \bigstar }}}

_______________________________

Similar questions