In the shown mass pulley system, pulleys and string are massless. The one end of the string is pulled by the force F=2mg. The acceleration of the block will be
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Answer:
3g
Explanation:
1) Let the tension in the string attached to the Force be T.
Then, T=F=2mg
2) Now,
As shown in figure attached,
Using Force equation,
2T-mg=ma
=>2*2mg-mg=ma
=>4mg-mg=ma
=>3mg=ma
=>a=3g
Hence, the acceleration of block of mass 'm' is 3g in upward direction.
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Explanation:
T = 2mg
2T - mg = ma
2 × 2mg - mg = ma
4mg - mg = ma
3mg = ma
3g = a
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