Question

calculate the tension in a string that whirls a 2 kg-toy in horizontal circle of radius 2.5 m when it move at 3 m/s

Answer 1

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Answer 2

Answer: [100% CORRECT]

7.2 N

Explanation:

Given: Mass of the Toy (m) = 2 kg

           Radius of the horizontal circle, (R) = 2.5 m

           Velocity (v) = 3 m/s

Tension of Spring, Fc = mv2/R = 2 x (3)2/ 2.5 = 2 x 9/2.5 = 18/2.5

= 18/2.5

= 7.2 N