Math, asked by aman52040, 1 year ago

I have a total of Rs 300 in coins of deamination Rs 1-2 and rs5 the number of Rs 2 points is 3 times the number of Rs 5 coins the total number of coins is 160 how many coins of each dominations are with in me

Answers

Answered by aastha7535
0
We have,
Total coins=160
Coins of denomination Rs. 5= x
Coins of denomination Rs. 2= 3x
Coins of denomination Rs. 1= 160-(3x+x)
=160-4x
Now,
Amount of Rs.5= Rs. 5*x
= Rs. 5x
Amount of Rs.2= Rs. 2*3x
= Rs. 6x
Amount of Rs.1= Rs. 1(160-4x)
= Rs. 160-4x
A/q
Amount of Rs.5+Amount of Rs.2+Amount of Rs.1 = Rs. 300
5x+6x+160-4x=300
11x-4x= 300-160
7x= 140
x=140/7
x=20
So,
Coins of denomination Rs. 5= x=20

Coins of denomination Rs. 2= 3x= 3*20=60

Coins of denomination Rs. 1 =160-4x
=160-(4*20)
=160-80
=80




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