I have a total of Rs 300 in coins of demand denominations Rs 1 Rs 2 and 5 number of Rs 2.3 times the number of the total number of coins is 160 how many of denomination are with me?
Answers
Answered by
0
Answer:
Step-by-step explanation:
let the no. of rs 5 coins be x
& the no. of rs 1 coin be y
& no. of rs 2 coins be 3 x
a.q.t total no. of coins = 160
x+3x+y=160
4x + y = 160 eq. 1
again a.q.t total rs = 300
5x + 2(3x) + 1y = 300
11x + y = 300 eq. 2
by elimination method
on subtracting both the equations
4x + y = 160
-11x -y = -300
=-7x =-140
x =20
on putting the the value of x in eq 2
4(20) + y =160
80 + y = 160
y =80
now,
no of rs 2 coins = 3(20)
= 60
no. of rs 5 coins = 20
no. of rs 1 coins=80
Answered by
0
Answer:
Answer : x=80, y=60 & z=20
Step-by-step explanation:
Attachments:
Similar questions