I have a total of Rs 300 in coins of denomination Rs 1 Rs 2 and Rs 5 the numbers of Rs 2 coins is 3 times the number of rupees 5 coins the total number of coins is 160 how many coins of each denomination are with me
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let the no. of Re 1 coins be x
the no. of Rs 2 coins be 2x
and the no. of Rs 5 coins be 5x
According to the question,
x+2x+5x=160
=>8x=160
=>x=160/8
=>x=20
Therefore, total no. of re 1 coins=x =20
total no. of Rs 2 coins=2x =2×20 = 40
and total no. of Rs 5coins=5x =5×20 =100
the no. of Rs 2 coins be 2x
and the no. of Rs 5 coins be 5x
According to the question,
x+2x+5x=160
=>8x=160
=>x=160/8
=>x=20
Therefore, total no. of re 1 coins=x =20
total no. of Rs 2 coins=2x =2×20 = 40
and total no. of Rs 5coins=5x =5×20 =100
harshraj1410:
this ans is wrong
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0
Answer:
Answer : x=80, y=60 & z=20
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