Question

I have a total of Rs.300 in coins of dominations Re.1,Rs.2 and Rs.5. The number of Rs.2 coins. The total number of coins is 160. How many coins of dominations are with me.

Answer 1

about....: Let the present age of Ravi = m year
Age of Ravi after 15 years = m + 15 year

According to question, age of Ravi will be four times of his present age.
i.e. Age of Ravi after 15 year = 4 x present age of Ravi
⇒ m + 15 = 4 x m
⇒ m + 15 = 4 m

After transposing m to RHS, we get
15 = 4m – 3
⇒ 15 = 3m

After dividing both sides by 3, we get



Thus, Ravi’s present age = 5 year Answer

Answer 2

let the no. of rs 5 coins be x

& the no. of rs 1 coin be y

& no. of rs 2 coins be 3 x

a.q.t total no. of coins = 160

x + 3x+y = 160

4x + y = 160 eq. 1

again a.q.t total rs = 300

5x + 2(3x) + 1y = 300

11x + y = 300 eq. 2

by elimination method

on subtracting both the equations

4x + y = 160

-11x -y = -300

=-7x =-140

  x =20

on putting the the value of x in eq 2

4(20) + y =160

80 + y = 160

y =80

now,

no of rs 2 coins = 3(20)= 60

no. of rs 5 coins = 20

no. of rs 1 coins=80

hey mate...

here's your answer...