I have a total of Rs. 400 in coins of denomination Re. 1, Rs. 2 and Rs. 5. The number of Rs. 2 coins is 3 times the number of Rs. 5 coins. The total number of coins is 160. How many coins of each denomination are with me?
Answers
Answer:
no. of Rs. 5 coins = 40
no. of rs. 2 coins = 80
no. of rs 1 coins = 40
Step-by-step explanation:
let no. of rs. 5 coins be x. since, 2( no. of rs. 2 coins) = no. of rs. 5 coins,
no. of rs. 2 coins = 2x.
and let no. of rs 1 coins be y.
total no. of coins = 160
therefore, x+ 2x+ y = 160
3x + y = 160...
.eq 1
+ y = 400
.eq 2
total amount = rs. 400
which implies, 5x + 2(2x) 9x+y=400...
(eq 2) - (eq 1),
9x + y = 400
3x + y = 160
6x = 240
x = 40
therefore, 2x = 80
sub value of x in eq 1,
3x + y = 160
120 + y = 160
y = 40
therefore,
no. of Rs. 5 coins = 40
no. of rs. 2 coins = 80
no. of rs 1 coins = 40
Answer:
Given :-
- I have a total of Rs 400 in coins of denomination Re. 1, Rs. 2 and Rs. 5.
- The numbers of Rs. 2 coins is 3 times the number of Rs. 5 coins.
- The total number of coins is 160.
To Find :-
- How many coins of each denomination are with me.
Solution :-
Let,
Given that :
The number of Rs. 2 coins is 3 times the number of Rs. 5 coins.
Now,
According to the question :
Hence, the required coins are :
✫ Number of Rs 5 coins :-
➳ x
➳ Rs 34
✫ Number of Rs 2 coins :-
➳ 3x
➳ 3(34)
➳ 3 × 34
➳ Rs 102
✫ Number of Re 1 coins :-
➳ 160 - 4x
➳ 160 - 4(34)
➳ 160 - 136
➳ Rs 24
The number of Re 1 coins is Rs 24, number of Rs 2 coins is Rs 102 and the number of Rs 5 coins is Rs 34 .