I have atormtal of rs 300 in coins of denomination rs 1 rs 2 rs 5.the no of rs2 coinin 3 time the number of 5 coins .the total number of coin in 160 .how many coin ofeach denominotion are either me.how to slove this
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Let rs1 coins=x, rs2 coins =y, rs5 coins =z
x+y+z=160
y=3z
x+2y+5z=300
Therefore
x+4z=160
x+11z=300
z=20
x=80
y=60
Hope it helps
If yes please mark brainliest
x+y+z=160
y=3z
x+2y+5z=300
Therefore
x+4z=160
x+11z=300
z=20
x=80
y=60
Hope it helps
If yes please mark brainliest
Answered by
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Answer:
Answer : x=80, y=60 & z=20
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