I have difficulty in question 3
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Answer:
cubic polynomial=
(X)cube-{6x} square-x-30
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Step-by-step explanation:
zeroes of polynomial are 5,3,–2
sum of zeroes=5+3+(–2)=6
sum of zeroes taken two at a time=5×3+3×(–2)+(–2×5)= –1
product of zeroes=5×3×(–2)=–30
substitute values in
《k(x^3–x^2(sum of zeroes)–x(sum of zeroes taken 2 at a time)+product of zeroes)》
K(x^3 –x^2(6)–x(–1)+30)
K(x^3–6x^2+x–30) (( k=1)
x^3‐6x^2+x–30 is cubic polynomial
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