Question

I have two bags of counters. The first bag contains two red counters and one blue counter. The second bag contains one red counter, one blue counter and one yellow counter.

I take one counter from both bags.

a) what is the probability that the two will be the same?

b) What is the probability that exactly one of the counters will be red?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer: a) 3/12 b)7/12

Step-by-step explanation:

A)2/3 of the first bag is red. 1/4 of the second bag is red. 2/3 x 1/4 = 2/12

1/3 of the first bag is blue. 1/4 of the second bag is blue. 1/3 x 1/4= 1/12

2/12 + 1/12 = 3/12.

i have attached the diagram which might help.

3/12

b)  Possible combinations - RR, RB, RY, RY, RR, RB, RY, RY, BR, BB, BY, BY.

There are 12 possible combinations.

if we remove RR, RR, BB, BY, BY. We are left with 7 combinations that have one red in them

7/12