Question

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${\bold{Explanation\:Required}}$​

Answer 1

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Answer 2

Answer:

AD=20cm

Step-by-step explanation:

let angle CAB=⊙

w.k.t. in triangle ABC

Cos ⊙=AB/BC

BC=CD+BD=41

cos⊙=AB/41 equation 1

now, in triangle ADB

angle D is right angled

so, cos ⊙=BD/AB

Cos ⊙=16/AB equation 2

in both equation 1 and 2 L.H.S are equal so R.H.S is also equal

i.e., AB/41=16/AB

AB^2=16×41

AB^2=656

Now in triangle ABD

By applying phthogoreas theorem

AB^2=AD^2+BD^2

656=AD^2+256

AD^2=400

AD=20cm