I hope that this image could be adequate to understand.
Attachments:
![](https://hi-static.z-dn.net/files/dab/6cba1ca081d22b9935d1dc2c3412b6a3.jpg)
Answers
Answered by
2
Hope it's helpful to you.
Please mark as Brainlist answer.
Attachments:
![](https://hi-static.z-dn.net/files/dd6/82ad6bf1a82cc6c4ecc1a3a7aa959ddf.jpg)
Answered by
2
Answer:
AD=20cm
Step-by-step explanation:
let angle CAB=⊙
w.k.t. in triangle ABC
Cos ⊙=AB/BC
BC=CD+BD=41
cos⊙=AB/41 equation 1
now, in triangle ADB
angle D is right angled
so, cos ⊙=BD/AB
Cos ⊙=16/AB equation 2
in both equation 1 and 2 L.H.S are equal so R.H.S is also equal
i.e., AB/41=16/AB
AB^2=16×41
AB^2=656
Now in triangle ABD
By applying phthogoreas theorem
AB^2=AD^2+BD^2
656=AD^2+256
AD^2=400
AD=20cm
Similar questions