(i) If an angle of a rhombus is 50º, find the size of the angles of one of the triangles which are formed by the diagonals.
I know the answer it is 65,90,25. but please explain me how it come
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Answer:
Since, in the tri.ABC, angle CAB = angle BCA = 50°.
From the angle sum property of a triangle, the sum of all angles of a triangle is 180°.
i.e., angle BAC+ angle BCA +angle ABC=180°.
50°+50°+ angle ABC=180°.
Therefore, the angle ABC =80°.
by the angle sum property of a triangle.
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