i) If arc AXB and arc AYB are corresponding arc and m(arcAXB)=120°. Then m(arc AYB)=?
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Answered by
1
Answer:
Consider that arc AXB is the minor arc and arc AYB is the corresponding major arc. ...
We have, m(arc AXB) = 120°.
So, m(arc AYB) = 360∘ − m(arc AXB)
= 360∘ − 120∘ = 240∘
Hence, the correct answer is option 240°.
Answered by
1
Answer:
60
Step-by-step explanation:
180 - 120 = 60
answers = AYB is 60°
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