(i) If the point (-1 ,- 5) lies on the graph of the linear equation
3x = ay + 7, then find the value of ’a’.
(ii) Give the equations of any two lines passing through
the point (3 ,4).
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Answer:
3x = ay + 7
put x= -1 , y = -5
3(-1) = a(-5) + 7
-3 = -5a +7
-3-7 = -5a
-10 = -5a
a= 10/5
a= 2
equation of line passing thru the points (3 ,4) are
3x +y = 13
x+4y = 19
x+y = 7
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