(i) In the adjoining figure, AD = DC and AB = BC then check whether AABDE ACBD.
(ii) Prove that BD bisects angleB as well as angleD?
✨Please answer briefly✨
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I think so this answer will help you
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In triangle ∆ADB and ∆CDB
AD=DC
AB=CB
DB=DB(COMMON)
so ∆ABD CONGURENT ∆CBD
SO <CDB =<ADB
so it bisects it
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