Chinese, asked by DIVRAJTHAROL4868, 1 year ago

I-iodopropane undergoes faster e2 elemination than i-chloropropane .Explain

Answers

Answered by tanishkasri
0
pls post the questions
Answered by loganyadav990
0

Answer:

2-Chloropropane will undergo substitution faster than 1-chloro-2,2-dimethylpropane.

The acetylide anion, HC≡C⁻, is the conjugate base of the extremely weak acid, acetylene.

So it is both a powerful nucleophile and an extremely strong base — about a billion times as strong as hydroxide ion.

It undergoes

S

N

2

reactions with methyl and primary alkyl halides.

But acetylide ion is such a strong base that it undergoes mainly

E2

eliminations with 2° alkyl halides.

And it undergoes only

E2

elimination with 3° alkyl halides.

An

S

N

2

reaction goes by backside attack at the α carbon atom.

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