I is not finitely generated but all ideal containig i is finitely generated example
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If I is an ideal in a ring R such that I is not finitely generated and every ideal properly containing I is finitely generated, then I is prime.
Let I be a non-finitely generated ideal and let a,b∈R such that a,b∉I. Then a∈I′ such that I′ is finitely generated and I′ properly contains I; b∈I′′ such that I′′ is finitely generated and I′′ properly contains I. I am having difficulties in showing that ab∉I.
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Hey mate......
Here is the correct answer :
I is an imaginary word.......
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Here is the correct answer :
I is an imaginary word.......
I hope that it was helpful to you.............
If you want these type of answers..... so you can follow me
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