Question

I’ll give 5 stars to whoever can answer this ASAP.

Answer 1

According to Angle SUM Property

50+41+x=180

91+x=180

x=180-91

x=89°

Hope it helps

Mark it as BRAINLIEST if you are satisfied with the answer

Answer 2

$\huge\bf{\underline{\red{Solution:-}}}$

Given :-

A triangle and the two angles of that triangle

=> 41° and 50°

To find :-

We have to find the third angle of triangle which is x

Now

$\bf\underline{\red{\:\:\:A.T.Q\:\:\:}}$

$\underline{\dag{\sf{\:\: Sum\:of\: Angles\:of\: triangle=180{}^{\circ}}}}$

$\sf\implies 50{}^{\circ}+41{}^{\circ}+x=180{}^{\circ}\\ \\ \sf\implies 91{}^{\circ}+x=180{}^{\circ}\\ \\ \sf\implies x=180{}^{\circ}-91{}^{\circ}\\ \\ \sf\implies x= 89{}^{\circ}$

So the value of x is 89°

$\boxed{\sf{x=89{}^{\circ}}}$

Extra information related to triangle :-

•Perimeter of triangle =Sum of all sides

• Area of triangle =1/2×base ×height

• And By heron's formula

$\sf\bullet Area=\sqrt{s(s-a)(s-b)(s-c)}$

• where. s = semi perimeter

• And a,b, and c are the sides of triangle .