Question

I
Locate
$\sqrt{?}$
3
on
the
number line​

Answer 1

answer is on above

pl mark this as brainliest answer

Answer 2

⦁First construct the BD of unit length perpendicular to OB.

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⦁Then apply the Pythagoras theorem $\rm{OD = \sqrt{(\sqrt{2})^{2} + 1^{2} = \sqrt{3}}}$

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⦁We can locate $\rm{\sqrt{3}}$ on number line by using a compass.

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⦁We know that, O is the center and radius OD. Now let's draw an arc which intersects the number line at the point Q.

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⦁Therefore, now the point Q = $\rm{\sqrt{3}}$