Question

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I
LULULL
WW.
et axes applied to a train moving at 90 km/h
Euce a retardation of 5 m/s? What distance
Fit cover before coming to a stop ?​

Answer 1

Answer:

0.5 m

Explanation:

the speed of train is 90km/hr = 25m/s

retardation = 5m/s²

using the equation v² - u2 = 2as

5² - 0² = 2 ×25 s

25 = 50s

S = 1/2 ans