Question

I need a help with a Math question pls answer it with step by step explanations. ​

Answer 1

Answer:

Step-by-step explanation:

Lets start the problem by squaring both sides,

we get,

$3 + \frac{(4+\sqrt[]{x+3)} ^{2} }{6} = 3^{2}$

$3 + \frac{(4+\sqrt[]{x+3)} ^{2} }{6} = 9$

$\frac{(4+\sqrt[]{x+3)} ^{2} }{6} = 9-3$

$\frac{(4+\sqrt[]{x+3)} ^{2} }{6} = 6$

$\frac{(4+\sqrt[]{x+3)} ^{2} }{1} = 36$

splitting the numerator,

16 + x+3 + 8√x+3  = 36

19 + x + 8√x+3   = 36

x+ 8√x+3  = 17

squaring both sides we get,

$x^{2} + 64(x+3) = 17^{2}$

$x^{2} +64x+192=289$

$x^{2} +64x+192-289=0$

$x^{2} +64x-97=0$

solve for x to get the answer

HOPE IT HELPS

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