i need a help with this sum...please do help me
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If x^3+6x^2+kx+6 is divisible by x+2 then
On putting
x+2=0
x=-2 the answer will come zero.
(-2)^3+6×-2+(-2k)+6=0
-8-12-2k+6=0
-14=2k
k=-7
On putting
x+2=0
x=-2 the answer will come zero.
(-2)^3+6×-2+(-2k)+6=0
-8-12-2k+6=0
-14=2k
k=-7
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pls mark brainiest
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