Question

I need a proper solution of question 10 quickly.
Please help me !!!

Answer 1

Heya!
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↪Given that :
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▪ABCD is a Square . BX = BY .


1. > ∆DCX is Congruent to ∆DAY


-> We have ,

- Angle C = Angle A [ 90° Each ]

- DC = AD [ Sides of a Square are Equal ]

-Angle D = Angle D [ Common ]



⭐Hence ∆DCX is Congruent to ∆DAY < ASA Criteria of Congruence >





2> . DY = DX


-> DY = DX < BY C.P.CT >




3> Angle DXC = Angle DYA


-> This is proved by C.PC.T as well !

->> C.P.C.T : Corresponding Parts of Congruent Triangles !

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Answer 2

here is your answer
hope it helps

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