i need all formulas in maths class 10 (CBSE)...plz urgent
dishantsinghom:
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try to take it from CBSE guide app or take help from Google .it is also given in the end of each chapter .if you can see in the book it will literally clear.I hope it helps if it heps plss mark as brainliest.
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Algebra:
(a + b)2 = a2 + 2ab + b2
(a – b)2 = a2 – 2ab + b2
(a + b) (a – b) = a2 – b2
(x + a)(x + b) = x2 + (a + b)x + ab
(x + a)(x – b) = x2 + (a – b)x – ab
(x – a)(x + b) = x2 + (b – a)x – ab
(x – a)(x – b) = x2 – (a + b)x + ab
(a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – b3 – 3ab(a – b)
(x + y + z) 2 = x2 + y2 + z2 + 2xy + 2yz + 2xz
(x + y – z) 2 = x2 + y2 + z2 + 2xy – 2yz – 2xz
(x – y + z)2 = x2 + y2 + z2 – 2xy – 2yz + 2xz
(x – y – z)2 = x2 + y2 + z2 – 2xy + 2yz – 2xz
x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz -xz)
x2 + y2 = 1212 [(x + y)2 + (x – y)2]
(x + a) (x + b) (x + c) = x3 + (a + b +c)x2 + (ab + bc + ca)x + abc
x3 + y3 = (x + y) (x2 – xy + y2)
x3 – y3 = (x – y) (x2 + xy + y2)
x2 + y2 + z2 -xy – yz – zx = 1212 [(x-y)2 + (y-z)2 + (z-x)2]
Powers:
amxan = am+n
aman=am−naman=am−n
(am)n = amn
(ambn)p = ampb np
a-m = 1am1am
amn=am−−−√namn=amn
Rules of Zero:
a1 = a
a0 = 1
a*0 = 0
a is undefined
Linear Equation:
Linear equation in one variable ax + b = 0, x = – −ba−ba
Quadratic Equation: ax2 + bx + c = 0 x = −b±b2−4ac√2a−b±b2−4ac2a
Discriminant D = b2 – 4ac
Hope helps you
Mark me brainliest
(a + b)2 = a2 + 2ab + b2
(a – b)2 = a2 – 2ab + b2
(a + b) (a – b) = a2 – b2
(x + a)(x + b) = x2 + (a + b)x + ab
(x + a)(x – b) = x2 + (a – b)x – ab
(x – a)(x + b) = x2 + (b – a)x – ab
(x – a)(x – b) = x2 – (a + b)x + ab
(a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – b3 – 3ab(a – b)
(x + y + z) 2 = x2 + y2 + z2 + 2xy + 2yz + 2xz
(x + y – z) 2 = x2 + y2 + z2 + 2xy – 2yz – 2xz
(x – y + z)2 = x2 + y2 + z2 – 2xy – 2yz + 2xz
(x – y – z)2 = x2 + y2 + z2 – 2xy + 2yz – 2xz
x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz -xz)
x2 + y2 = 1212 [(x + y)2 + (x – y)2]
(x + a) (x + b) (x + c) = x3 + (a + b +c)x2 + (ab + bc + ca)x + abc
x3 + y3 = (x + y) (x2 – xy + y2)
x3 – y3 = (x – y) (x2 + xy + y2)
x2 + y2 + z2 -xy – yz – zx = 1212 [(x-y)2 + (y-z)2 + (z-x)2]
Powers:
amxan = am+n
aman=am−naman=am−n
(am)n = amn
(ambn)p = ampb np
a-m = 1am1am
amn=am−−−√namn=amn
Rules of Zero:
a1 = a
a0 = 1
a*0 = 0
a is undefined
Linear Equation:
Linear equation in one variable ax + b = 0, x = – −ba−ba
Quadratic Equation: ax2 + bx + c = 0 x = −b±b2−4ac√2a−b±b2−4ac2a
Discriminant D = b2 – 4ac
Hope helps you
Mark me brainliest
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