Math, asked by hari70, 1 year ago

I need an solution ASAP

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Answered by serena777
2
A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have aSunday. So the probability of 53 Sundays is 2/7.

serena777: A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have aSunday. So the probability of 53 Sundays is 2/7.
loveme111: hi
Answered by Anonymous
1
see my notes

Hope it's help you! ! !
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