i need explanation yaaro
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parakhcmd:
hey
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Option c. Is correct
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so according to your given answer the upper two capacitors are in parallel
and one single present below is in series with them
so net capacitance of upper two = 2A*absilonnot/d
net capacitance
1/c(net)=1/(2Aabsilonnot/d)+1/(Aabsilonnot/d)
1/c(net)=3/(2Aabsilonnot/d)
c(net)=(2Aabsilonnot/d)/3
c(net)=6Aabsilonnot/d
hope u will understand well
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