Question

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Answer 1

Answer:

in ∆ABC, PR||CB

therefore by Basic Proportionality theorem

AR. = AP ........(1)

RB. PC

in ∆ACD, PQ||CD

therefore by Basic Proportionality theorem

AQ. = AP ........(2)

QD. PC

from (1) and (2)

AR. = AQ

RB. QD

Answer 2

Answer:

To prove AQ/QD = AR/RB

Step-by-step explanation:

In triangle ADC

AQ/QD = AP/PC (Theorem)..1

Now in triangle ABC

AR/RB = AP/PC (Theorem)..2

From 1 and 2

Since the RHS are equal

AQ/QD =AR/RB