Math, asked by coolcrush50, 6 months ago

i need help to solve this quadratic formula i need a full solution thats all
1. X^2+5x-14 ​
2. 2x^2+8x-10=0
3.2x^2+3x=27

Answers

Answered by MihirRaj11
86

\huge{\underline{\bf\red{Questi {\mathbb{O}} n} :}}

Solve the quadratic equations :-

  •  \boxed{ {x}^{2} + 5x - 14 = 0 }

  •  \boxed{2 {x}^{2} + 8x - 10 = 0 }

  •  \boxed{2 {x}^{2} + 3x - 27 = 0 }

\huge{\underline{\bf{\color{lightgreen}{Soluti {\mathbb{O}} n}}\ :}}

 \underline{ \underline{ \bf \blue{option} \ \red{(i)}}}

\begin{aligned} \\  \qquad {x}^{2} + 5x - 14  & = 0 \\  \\  \implies  \ \ {x}^{2}  + (7 - 2)x - 14 & = 0 \\  \\  \implies \ \ \:  {x}^{2} + 7x - 2x - 14 & = 0 \\  \\  \implies x(x + 7) - 2(x + 7) & = 0 \\  \\  \implies \qquad \ (x + 7)(x - 2) & = 0 \\  \\  \implies(x + 7) = 0 \quad \boxed{or} \quad &(x - 2) = 0 \\  \\  \implies x =  - 7 \qquad \ \ \ \boxed{or} \quad& x = 2& & & \end{aligned}

\underline{ \underline{ \bf \blue{option} \ \red{(ii)}}}

\begin{aligned} \\  \qquad 2{x}^{2} + 8x - 10  & = 0 \\  \\  \implies \qquad \quad \ \ {x}^{2}  + 4x - 5& = 0 \\  \\  \implies  \quad {x}^{2}  + (5 - 1)x - 5 & = 0 \\  \\  \implies \quad \ \ \  {x}^{2} + 5x - x - 5 & = 0 \\  \\  \implies x(x + 5) - 1(x + 5) & = 0 \\  \\  \implies \qquad \ (x + 5)(x - 1) & = 0 \\  \\  \implies(x + 5) = 0 \quad \boxed{or} \quad &(x - 1) = 0 \\  \\  \implies x =  - 5 \qquad \ \ \ \boxed{or} \quad& x = 1& & & \end{aligned}

\underline{ \underline{ \bf \blue{option} \ \red{(iii)}}}

\begin{aligned} \\  \qquad 2{x}^{2} + 3x - 27  & = 0 \\  \\  \implies  \quad 2{x}^{2}  + (9 - 6)x - 27 & = 0 \\  \\  \implies \quad \:  2 {x}^{2} + 9x - 6x - 27 & = 0 \\  \\  \implies x(2x + 9) - 3(2x + 9) & = 0 \\  \\  \implies \qquad  \ \ \ (2x + 9)(x - 3) & = 0 \\  \\  \implies \ \ (2x + 9) = 0 \quad \boxed{or} \quad &(x - 3) = 0 \\  \\  \implies \ \ \ x =  -  \frac{9}{2}  \qquad \ \ \ \boxed{or} \quad& x = 3& & & \end{aligned}

\red{\rule{5.5cm}{0.02cm}}

Method Used :-

\boxed{ \bf \quad Middle \quad Term \quad Splitting \quad }

\purple{\rule{7.5cm}{0.02cm}}

\Large{ \mid {\underline{\underline{\bf\green{BrainLiest \ AnswEr}}}} \mid }

Answered by Mihir1001
114

 \fbox\purple{A}\fbox\red{N}\fbox\green{S}\fbox\orange{W}\fbox\pink{E}\fbox\purple{R}

1

  • x =  - 7  \quad \boxed{or} \quad x = 2

2

  • x =  - 5 \quad \boxed{or} \quad x = 1

3

  • x =  -  \dfrac{9}{2}  \quad \boxed{or} \quad x = 3

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{\fcolorbox{white}{lightgreen}{{\footnotesize{{$ \:  \color{white}{\checkmark} $ }}} \ {\small{ \sf Verified \: answer}}}}

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