Question

I need solution for this.

Answer 1

Here is your answer > >
DE||QR
<EAP=<PAB(AP is the bisector of <EAB)
<ABP=<PBR (BP is the bisector of <RBA)
<PAB+<PBR=180 (Co-interior angles)
1/2 <PAB+1/2 <PBR=180/2
<PAB+<ABP=90
In triangle APB
<PAB+<ABP+<APB=180 (Angle sum property of triangle)
90+<APB=180
<APB=90
Hope it helps!
Thankyou ☆ ☆
Bebrainly