Question

i need some help in active
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Answer 1

Answer:

The work W done by the net force on a particle equals the change in the particle’s kinetic energy KE:

W

=

Δ

KE

=

1

2

mv

2

f

−

1

2

mv

2

i

where vi and vf are the speeds of the particle before and after the application of force, and m is the particle’s mass.

Derivation

For the sake of simplicity, we will consider the case in which the resultant force F is constant in both magnitude and direction and is parallel to the velocity of the particle. The particle is moving with constant acceleration a along a straight line. The relationship between the net force and the acceleration is given by the equation F = ma (Newton’s second law), and the particle’s displacement d, can be determined from the equation:

v

2

f

=

v

2

i

+

2

ad

obtaining,

d

=

v

2

f

−

v

2

i

2

a

The work of the net force is calculated as the product of its magnitude (F=ma) and the particle’s displacement. Substituting the above equations yields:

W

=

Fd

=

ma

v

2

f

−

v

2

i

2

a

=

1

2

mv

2

f

−

1

2

mv

2

i

=

KE

f

−

KE

i

=

Δ

KE

LICENSES AND ATTRIBUTIONS

Answer 2

do you mean active passive ?