Question

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Answer 1

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Answer:

 Let the speed of car starting from A be 'x' km/h and speed of car starting from B be 'y' km/h.

Total distance=80 km

Also 1 hour 20 mins= 4/3 hour

As per given condition, When car moves in same direction,

Distance travelled by y= 8y km

Distance travelled by x= 8x= 80+8y

Now, Equation formed is 8x=80+8y

=> 8x-8y=80

=> x-y=10 ----(1)

Similarly, For opposite direction,

Distance travelled by x= (4/3)x

Distance travelled by y= (4/3) y

Also total distance covered= 4/3*x+4/3y

=> 80= 4x+4y/3

=> 240= 4x+4y

=> 60=x+y ----(2)

Solving Equation (1) and (2)

60=x+y ----(2)

x-y=10 ----(1)

=> x= 10+y ----(3)

Substituting the value of (3) in (2) we get,

60= 10+y+y

=> 60-10=2y

=> 50=2y

=> 25=y

Also, x=10+y=> x= 10+25=> x=35

Therefore Speed of car starting from A is 35km/h

Speed of car starting from B is 25km/h

Answer 2

let the speed of car A be x
let the speed of car B be y
8x-8y = 80
x- y = 10
x=10+y eq1.
4x/3 +4y/3 =80
x+y=60 eq2.
put eq1. in eq 2.
10+2y =60
y = 25

put y = 25 in eq1.
x= 25+10
x=35

speed of car A is 35 km/hr
speed of car B is 25km/hr

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