Math, asked by AdishAnil, 1 year ago

I need the answer of this with STEP BY STEP EXPLANATION.

best answer gets brainliest

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Answered by Anonymous
4

Sum of zeroes taking 2 at a time

= coefficient of x/coefficient of x^3

= c/a

product of zeroes = - constant/coeff.of x^3

= -d/a

let roots i am taking as p,q,r

1/p +.1/q + 1/r = pq + qr + pr)/ pqr

= c/a)/-d/a = -c/d


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Answered by Anonymous
3
here is your answer,mate
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