Question

I need the answer to this Question please...

Answer 1

Step-by-step explanation:⤵️

a) =>

in ∆ABC

(AC)^2=(AB)^2 + (BC)^2

➨ (15)^2 = (AB)^2 + (7)^2

➨ 225 = (AB)^2 + 49

➨ (AB)^2 = 176

➨ AB = 4√11

➨

horizontal distance of trees

= 4√11m

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B) =>

in ∆BAF

(BF)^2 = (AB)^2 + (AF)^2

➨ 20^2 = (4√11)^2 + (AF)^2

➨ 400 = 176 + (AF)^2

➨ AF = √224 = 4√14

➨ hight of taller tree

= 4√14m