Math, asked by dsfgvierhf, 1 year ago

I need the explanation of how it is done

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Answers

Answered by sonisiddharth751
6

Answer:

see picture.......

hope it helps you ✌️✌️

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Answered by Anonymous
38

Answer:

\underline{\bigstar\:\boldsymbol{According\:to\:the\:Question :}}

\dashrightarrow\sf\:\:\dfrac{2x\sqrt{x}- {\Large\frac{x^2}{2\sqrt{x}}}}{x}\\\\\\\dashrightarrow\sf\:\:\dfrac{{\Large\frac{2\sqrt{x} (2x\sqrt{x})\:-\:x^2}{2\sqrt{x}}}}{x}\\\\\\\dashrightarrow\sf\:\:\dfrac{{\Large\frac{(2 \:\times \:\sqrt{x} \: \times \: 2x\:\times\:\sqrt{x})\:-\:x^2}{2\sqrt{x}}}}{x}\\\\\\\dashrightarrow\sf\:\:\dfrac{{\Large\frac{4x^2\:-\:x^2}{2\sqrt{x}}}}{x}\\\\\\\dashrightarrow\sf\:\:\dfrac{{\Large\frac{3x^2}{2\sqrt{x}}}}{x}\\\\\\\dashrightarrow\sf\:\: \dfrac{3x^2}{2 \sqrt{x}} \times \dfrac{1}{x}\\\\\\\dashrightarrow\sf\:\: \dfrac{3x}{2 \sqrt{x}}\\\\\\\dashrightarrow\sf\:\: \dfrac{3x}{2 \sqrt{x} } \times \dfrac{ \sqrt{x} }{ \sqrt{x} }\\\\\\\dashrightarrow\sf\:\: \frac{3x \sqrt{x} }{2x}\\\\\\\dashrightarrow\:\: \large\underline{\boxed{\sf \dfrac{3 \sqrt{x} }{2}}}

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