Math, asked by twisha51, 2 months ago

i need the solution please​

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Answered by Anonymous
1

Answer:

hey mate here is the answer

Step-by-step explanation:

10. A = p×(1+r/100)²

1.44×p = p× (1+r/100)²

1.44 = (1+r/100)²

√ 1.44 = (1+r/100)

1.2 = (1+r/100)

1+2/10 = (1+r/100)

2/10 = r/100

20/100= r/100

r = 20 %

11. p = 4000, CI = 1324, n = 3 yrs

AMOUNT = 4000 +1324 = rs 5324

A = p(1+r/100)^n

5324 = 4000(1+r/100)³

(1+r/100)³ = 5324/4000= 1331/1000

(1+r/100)³ = (11/10)³

1+r/100 = 11/10

r/100= 11/10 -1 = 1/10

r = 10%

Answered by BelovedRose
0

Answer:

Here goes the solution,

10. Let the P is the principle sum of money and R is rate of interest.

SInce,

A = 1.44×P, T = 2 years

So, A = P( 1+R/100)^T

1.44P = P( 1+R/100)^2

( 1+R/100)^2 = 1.44

1+R/100 = 1.2

R/100 = 0.2

R = 20%

11. Given: P = Rs 4,000, C.I. = Rs 1,324 and n= 3 years

Now, A = P + I

A = Rs.(4,000+1,324) = Rs.5,324

5324 = 4000(1+R/100)^3

5324/4000 = (1+R/100)^3

1331/1000 = (1+R/100)^3

(1+R/100)^3-1331/1000-(11/10)^3 (1+R/100)= 11/10

R/100 = 11/10-1 = 1/10

R = 100/100 = 10%

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