i need the solution please
Answers
Answer:
hey mate here is the answer
Step-by-step explanation:
10. A = p×(1+r/100)²
1.44×p = p× (1+r/100)²
1.44 = (1+r/100)²
√ 1.44 = (1+r/100)
1.2 = (1+r/100)
1+2/10 = (1+r/100)
2/10 = r/100
20/100= r/100
r = 20 %
11. p = 4000, CI = 1324, n = 3 yrs
AMOUNT = 4000 +1324 = rs 5324
A = p(1+r/100)^n
5324 = 4000(1+r/100)³
(1+r/100)³ = 5324/4000= 1331/1000
(1+r/100)³ = (11/10)³
1+r/100 = 11/10
r/100= 11/10 -1 = 1/10
r = 10%
Answer:
Here goes the solution,
10. Let the P is the principle sum of money and R is rate of interest.
SInce,
A = 1.44×P, T = 2 years
So, A = P( 1+R/100)^T
1.44P = P( 1+R/100)^2
( 1+R/100)^2 = 1.44
1+R/100 = 1.2
R/100 = 0.2
R = 20%
11. Given: P = Rs 4,000, C.I. = Rs 1,324 and n= 3 years
Now, A = P + I
A = Rs.(4,000+1,324) = Rs.5,324
5324 = 4000(1+R/100)^3
5324/4000 = (1+R/100)^3
1331/1000 = (1+R/100)^3
(1+R/100)^3-1331/1000-(11/10)^3 (1+R/100)= 11/10
R/100 = 11/10-1 = 1/10
R = 100/100 = 10%