Question

I need the solution to these questions

Answer 1

Answer:

Step-by-step explanation:

a, Voltage in Parallel connection is equal.

So V= 6v

V= IR

i, R= 5 ohm

6/5=I

Current in first resistor is 1.2 amp

ii, R= 10 ohm

I= 6/10

Current in 2nd resistor is 0.6 amp

iii, R= 20 ohm

I= 6/20

Current in 3rd resistor is 0.3 amp

c, Effective resistance in parallel

$\frac{1}{R_{p} }$ =  $\frac{1}{R_{1} }$ + $\frac{1}{R_2}$ + $\frac{1}{R_3}$

${R_1}$ = 5

${R_2}$ = 10

${R_3}$ = 15

$\frac{1}{R_{p} }$ =$\frac{6+3+2}{30}$

    =$\frac{11}{30}$

Rp= 30/11

b, Total current in circuit is 2.2 amp

6*11/30=I

11/5=

2.2 amp