Question

(i) p(x) = x2 - x - 12​

Answer 1

Answer:

Answer in attachment

Hope it helps

Answer 2

Answer:

x² - x - 12

= x² - 4x + 3x - 12

= x ( x - 4 ) + 3 ( x - 4 )

= ( x + 3 ) ( x - 4 )

Now,

x + 3 = 0 , x - 4 = 0

=> x = - 3 => x = 4

.

. . The zeroes of x² - x - 12 are - 3 & 4