I Promise I Will Mark As Brainliest If You Answer This Question
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from the velocity time above
distance=s
time=t
acceleration=a
s=ar(OABC)
=(OA+BC)OC ÷2 (putting OA=u BC=v OC=t) =(u+v)t÷2
=(v-u)(v+u)÷2a or 2as=v2-u2
now its your turn!
distance=s
time=t
acceleration=a
s=ar(OABC)
=(OA+BC)OC ÷2 (putting OA=u BC=v OC=t) =(u+v)t÷2
=(v-u)(v+u)÷2a or 2as=v2-u2
now its your turn!
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Now Its My Turn To Complete My Promise
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