Question

(I) Prove that
relation on set of
reals R is
equality relation. ​

Answer 1

I dont got whats the Q.........

Answer 2

Answer:

Prove that the relation R is an equivalence relation, given that the set of complex numbers is defined by z1 R z2 ⇔[(z1-z2)/(z1+z2)] is real. ... Check the reflexive, symmetric and transitive property of the relation x R y, if and only if y is divisible by x, where x, y ∈ N.