Question

(i) q(y) = 2y3 - 4y + VII at y = 1​

Answer 1

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Answer 2

Answer:

Given, q(y)=2y

2

−4y+

11

We need to find value of polynomial at y=1

Put the value y=1 in the given polynomial, we get

q(y)=2(1)

2

−4(1)+

11

⇒q(y)=2−4+

11

⇒q(y)=2−4+3.32

⇒q(y)=1.32

Therefore, q(y)=1.32

Step-by-step explanation:

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